How do you find the maximum height reached by a ball?

Use the vertical motion model, h = -16t2 + vt + s, where v is the initial velocity in feet/second and s is the height in feet, to calculate the maximum height of the ball.

How do you find the greatest height reached?

h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.

What is the maximum height reached by a ball if it is projected with an initial velocity of 4i 3j?

45 m. Was this answer helpful?

At what time does the ball reach its maximum height?

1 Expert Answer So the highest point on the parabola is when x=3, or in our case t=3. So the ball reaches its maximum height after 3 seconds.

What is the maximum height reached by an object that is thrown?

The maximum height reached by an object thrown up with an initial velocity u is given by h=2gu.

What is the formula of maximum range?

Maximum Range of Projectile Now that the range of projectile is given by R = u 2 sin ⁡ 2 θ g , when would be maximum for a given initial velocity .

When a ball reaches maximum height What is the acceleration?

The acceleration of the ball would be equal to the acceleration due to gravity caused by gravitational pull or force exerted by the earth on the ball. Its value is approximately 9.8 m/s^2 and its direction would be downwards towards the center of the earth.

How do you know when a projectile reaches its highest point?

The highest point in any trajectory, called the apex, is reached when vy = 0. Since we know the initial and final velocities, as well as the initial position, we use the following equation to find y: v2y=v20y−2g(y−y0).

When the height is maximum in projectile motion?

When the object reaches a vertical velocity of zero magnitudes, then it will be at its maximum height of the projectile.

How do you find the maximum distance in physics?

The equation for the distance traveled by a projectile being affected by gravity is sin(2θ)v2/g, where θ is the angle, v is the initial velocity and g is acceleration due to gravity. Assuming that v2/g is constant, the greatest distance will be when sin(2θ) is at its maximum, which is when 2θ = 90 degrees.

How do you find the maximum height and range?

hmax = h + V₀² / (4 * g) and in that case, the range is maximal if launching from the ground (h = 0). if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that’s the case of horizontal projectile motion.

When a ball is thrown upward What is its velocity at its highest point?

Therefore, velocity at the top is zero and acceleration is acceleration due to gravity (g). Was this answer helpful?

What is the velocity of the ball when it reaches its highest point?

At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth (see figure 1).

How do you find maximum height with velocity?

What is the formula of maximum range and maximum height of the particle in projectile motion?

Thus, the maximum height of the projectile formula is, H = u 2 sin 2 θ 2 g .

Why is the maximum range of a projectile 45?

The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.

What is maximum height in physics?

yo = 0, and, when the projectile is at the maximum height, vy = 0. Note that the maximum height is determined solely by the initial velocity in the y direction and the acceleration due to gravity. It’s not affected by what’s happening in the x direction.

How do you find maximum height with velocity and angle?

1. The maximum heighth of a projectile launched with initial vertical velocityv0y v 0 y is given by. h= v20y2g.
2. The maximum horizontal distance traveled by a projectile is called the range.

When an object was thrown upwards reaches its highest point which is true?

When an object is thrown upwards, the velocity at the highest point is zero while acceleration is equal to the acceleration due to gravity.

When an object is thrown vertically upward on reaching the highest point?

When you throw a ball up in the air, its speed decreases, until it momentarily stops at the very top of the ball’s motion. Its acceleration is −9.8 ms−2 at the very top since the body is moving upward against the gravity. In other words, the acceleration due to gravity g=9.8 ms−2↓.

What is velocity at the highest?

At the peak itself, the vertical velocity is 0 m/s; the velocity vector is entirely horizontal at this point in the trajectory. These concepts are further illustrated by the diagram below for a non-horizontally launched projectile that lands at the same height as which it is launched.

What is the maximum possible height a particle can attain?

Maximum possible height attained by a projectile is 2gu2, where u is initial velocity.

Why is 45 degrees the best launch angle mathematically?

A launch at 45 degrees would allow the ball to remain in the air for a longer time, but it would then be launched at a lower horizontal speed at the start and it would slow down more because of the longer flight time. An additional aerodynamic force arises if the ball is spinning.

Is the range of projectile is same at 30 and 60?

An object thrown up into the air at 60 degrees will have the same horizontal distance (or range) as if it were thrown at 30 degrees. The only difference is the height the objects go and the time they are in the air.

Is 45 degrees always the best angle of trajectory?

No matter what planet you’re on, how fast you do it, the best angle is always 45 degrees assuming no air resistance. And if you do it on that best angle, you’re going to travel s squared over g.