If you stand on a scale in an elevator accelerating upward, you feel heavier because the elevator’s floor presses harder on your feet, and the scale will show a higher reading than when the elevator is at rest. On the other hand, when the elevator accelerates downward, you feel lighter.
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How do you solve an elevator problem in physics?
support force F = mass x acceleration + weight For a mass m= kg, the elevator must support its weight = mg = Newtons to hold it up at rest. If the acceleration is a= m/s² then a net force= Newtons is required to accelerate the mass. This requires a support force of F= Newtons.
What will happen to a person’s weight when he is in a moving elevator?
From the above explanation and given condition when person in an elevator is moving at constant speed in such case the net acceleration will be zero. Thus we can say that person’s weight when he is in a moving elevator will not change because the apparent weight of the person will be equal to its true weight.
How do you calculate apparent weight in lift?
What is apparent weight formula?
The apparent weight of an accelerating object is the vector sum of its real weight and the negative of all the forces that produce the object’s acceleration a = dv/dt. wapparent = wreal – ma.
Do you feel heavier or lighter when riding on an escalator?
So, you actually feel a little heavier than usual when the elevator accelerates upward, and lighter than usual when the acceleration is down.
Why do you weigh less in an elevator?
This can also make you feel lighter: when the elevator slows down, you need to slow down with it. But gravity is always pulling you down, so for you to slow down, the floor needs to push up on you less, so gravity can slow you down. Since the floor pushes on you less, you feel lighter.
What happens to the weight of a body in a lift which has a net upward acceleration Class 11?
Answer: If you stand on a scale in an elevator accelerating upward, you feel heavier because the elevator’s floor presses harder on your feet, and the scale will show a higher reading than when the elevator is at rest. On the other hand, when the elevator accelerates downward, you feel lighter.
How do elevators work physics?
Does your weight change in the elevator?
When the elevator is moving, we will weigh our normal weight. Since we are already moving at the same speed as the elevator (up or down), nothing is affecting us to change our weight. However, when the elevator starts to go or stops, our body resists it.
When lift moves upward actual weight is?
So, when a lift accelerates upwards, the apparent weight of the person inside it increases. So, when a lift accelerates downwards, the apparent weight of the person inside it decreases. R = m (g-g) = 0. Thus, the apparent weight of the man becomes zero.
How do you find the apparent weight of a man in an elevator?
How do you calculate true weight in physics?
The weight of an object is defined as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity, w = mg.
What is the apparent weight of a man in a lift?
Apparent weight, R = m( g – a ). And as the lift accelerates downwards, the man’s apparent weight within it diminishes if a value increases and is more than g then the man’s apparent weight inside the lift is negative.
What is the apparent weight of the person when the elevator is falling freely?
Thus, the apparent weight of the man becomes zero. This is because both the man and the lift are moving downwards with the same acceleration ‘g’ and so there are no forces of action and reaction between the person and the lift. Hence a person develops a feeling of weightlessness when he falls freely under gravity.
How do you calculate the weight of an object in an elevator?
What is apparent weight physics?
: the weight of a body as affected by the buoyancy of a fluid (such as air) in which it is immersed, being the true weight minus the weight of the displaced fluid — compare archimedes’ principle.
How do you find weight from density and apparent weight?
Why does a weight feel heavier at the beginning of the lift?
Once the elevator begins accelerating upward, it is not only supporting your weight but also pushing upward into your feet in order to accelerate your body upward with it.
Does gravity change in an elevator?
When the elevator is moving, we will weigh our normal weight. Since we are already moving at the same speed as the elevator (up or down), nothing is affecting us to change our weight. However, when the elevator starts to go or stops, our body resists it.
Why might an elevator cable break during acceleration when lifting a lighter load than it normally supports at rest or at constant velocity?
In this acceleration range, the rope tension can increase in the range of 20% to 30% for typical acceleration values and according to equation (1). For this reason, the cable may break during acceleration even though it is carrying a lower load.
Why is a person’s weight the same in a stationary elevator as when the elevator is moving at a constant velocity?
Answer 2: From classical physics, Force = mass x acceleration. So, for a person at rest, their weight is simply their mass times the acceleration due to gravity. Now, for both cases you described, their weight would still be exactly the same since the elevator in both cases is traveling at constant speed.
Why does normal force change in an elevator?
This requires an increased normal force. When the elevator is accelerating downwards, it does not need to oppose gravity as much and so the normal force decreases to provide a net downward force from gravity. No changing mass is needed.
Is the tension in the cable of 1000 kg elevator is 1000 kg weight the elevator?
Answer. Given, the tension in the cable of 2000 kg elevator is 1000 kg weight .
When the elevator is accelerating upward the apparent weight of a man is?
(iii) When the elevator is accelerating upwards with acceleration a , we have
R- mg=ma
or R=m(g+a)
In this case , apparent weight becomes more .
(iv) If a=g,R=m(g-g)=0
So , the apparent weight of a person in an elevator falling down freely with an acceleration (=g) is zero .