# How long must a pendulum be on the moon where g 1.6 N kg to have a period of 2.0 s?

Hence, the length of the pendulum should be 0.162 meters to have a time period of 2 sec on the moon.

## How do you solve a pendulum problem?

1. The period of a simple pendulum is described by this equation. T = 2π√ ℓ g. Make length the subject. ℓ = gT2 4π2
2. Back to the original equation. Length and gravity are given. Period is the goal. T = 2π√ ℓ g. Weaker equatorial gravity in. T = 2π√
3. Repeat. T = 2π√ ℓ g. Stronger polar gravity in. T = 2π√ 0.993621386 m.

## How do you calculate the motion of a pendulum?

s(t) = smaxcos(ωt + φ), with ω2 = g/L. For small oscillations the period of a simple pendulum therefore is given by T = 2π/ω = 2π√(L/g). It is independent of the mass m of the bob. It depends only on the strength of the gravitational acceleration g and the length of the string L.

## How do you find the period of a pendulum physics?

pendulums. … each complete oscillation, called the period, is constant. The formula for the period T of a pendulum is T = 2π Square root of√L/g, where L is the length of the pendulum and g is the acceleration due to gravity.

## What is g in pendulum equation?

L = length of the pendulum. g = acceleration due to gravity. This worked example problem will show how to manipulate this equation and use the period and length of a simple pendulum to calculate the acceleration due to gravity.

## What is 2π √ LG?

The time period of a simple pendulum is given by T=2π√lg. The measured value of the length of pendulum is 10 cm known to 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution.

## What are the three laws of simple pendulum?

According to the laws of simple pendulum. A simple pendulum’s period is directly proportional to the square root of its length. A simple pendulum’s period is inversely related to the square root of gravity’s acceleration. A simple pendulum’s period is independent of its mass.

## How do you calculate period in physics calculator?

The formula for period is T = 1 / f , where “T” is period – the time it takes for one cycle to complete, and “f” is frequency.

## What is the formula for a period?

The period of a function f(x) is p, if f(x + p) = f(x), for every x. A function is said to be periodic if its value repeats after regular periods (intervals). The formula is Period, P = Period of parent function/ |Coefficient of x|

## How do you find the length of a pendulum with frequency?

L = g/(4π2f2) For example, the length of a pendulum that would have a frequency of 1 Hz (1 cycle per second) is about 0.25 meters.

## How do you find the time period and frequency of a pendulum?

Frequency is defined as the number of oscillations per unit time. Time = 4 sec. Time Period = (4/40) = 0.1 sec. Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

## What is the period on earth of a pendulum with a length of 2.4 m?

The period of the 2.4-m long pendulum is 3.11 seconds.

## What will be the frequency of simple pendulum if its length is 1m?

A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s.

## What is the period of a pendulum with a length of 1.4 m?

Now the length of the pendulum given is 1.4 m, and the gravitational acceleration is 9.8 m per second square. Now substitute the value to find out the period of oscillation that is two times 3.14 Times squirreled off 1.4 m over 9.8 m per second squared, Or the bill of oscillation for the pendulum has 2.4 seconds.

## What formula is v1 t1 v2 T2?

The relationship between volume and temperature is: V1 / T1 = V2 / T2 where V1 and T1 are the initial volume and absolute temperature and V2 and T2 are the final volume and absolute temperature (the Kelvin temperature, not the Celsius temperature).

## How do you find the length of a seconds pendulum?

On earth, the seconds pendulum has a constant length of approximately 1m. Q. The length of a second pendulum is 1m [ where g=9.8m/s2].

## How do I calculate g?

To calculate g force from velocity: Subtract initial velocity from final velocity. Divide the difference by time. Divide the resultant by the acceleration due to gravity, 9.81 m/s², to obtain the g force value.

## How do you find the value of g?

G is the universal gravitational constant, G = 6.674 x 10-11 m3 kg-1 s-2. M is the mass of the body measured using kg. R is the mass body radius measured by m. g is the acceleration due to the gravity determined by m/s2.

## How do I calculate amplitude?

The amplitude is the distance between the centerline and the peak or trough. x = A sin (ωt + ϕ) or x = A cos (ωt + ϕ) is the formula.

## Why is SHM important?

Whilst simple harmonic motion is a simplification, it is still a very good approximation. Simple harmonic motion is important in research to model oscillations for example in wind turbines and vibrations in car suspensions.

## How is T 2π √ l g derived?

In lecture, you derived the well-known formula for the period of a simple pendulum: ___ T = 2π √L/g . The derivation consists of applying Newton’s Law F = ma to a mass m suspended from a lightweight (massless) string of length L in a gravitational field of strength g.

## Is V √ p density dimensionally correct?

Solution. Since the dimensions of both sides of the equation are the same, the equation is dimensionally correct.

## How does Newton’s second law apply to A pendulum?

This law shows that since a pendulum moves side to side and not up and down it has no up and down forces acting on it. Newton’s second law is used in determining the net force on the pendulum by setting the gravitational force equal to the force of the string that pulls back up on the pendulum.