If you are accelerating down much less than the acceleration due to gravity, the tension on the bottom string is much less than the tension of the top string*. Because the tension is greater at the top, that string will break first.
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At which point the string is most likely to break?
So, the wire is most likely to break when the mass is at the lowest point.
How would you pull to get the upper string to break?
If the lower string is pulled slowly, the upper string eventually breaks, because it supports both the applied force and the hanging weight. However, if the lower string is suddenly jerked, it is the one which breaks.
Which string breaks if the lower string is jerked rapidly downward?
If you jerk the lower string downward, the lower string breaks, but the upper string survives, and the weight remains suspended from the ceiling. In contrast, if you slowly pull the lower string downward, only the upper string breaks, and the weight falls off.
Will string theory ever be proven?
Physicists have yet to produce any empirical evidence for either string theory, which was invented more than 40 years ago, loop-space theory or any other unified theory. They don’t even have good ideas for obtaining evidence.
Which rope will break first?
The longer rope will probably break first as, being longer, it has a bigger chance of flaws that will let it break. Hence the tension in the shorter rope will probably be higher when it breaks.
Why is tension greatest at bottom?
Tension and gravity are NOT “in the same direction”. The tension in the rope is always directed toward the middle of the circle. At the bottom, that means tension is UPWARD while gravitational force is directed DOWNWARD. The two are in opposite directions, not the same direction.
Why is tension 0 at the top of a vertical circle?
Minimum speed required by the particle at the highest point to complete the vertical circular motion is √ (g r). Hence, tension can be zero at the highest point.
When a ball attached to string is swung in a vertical circle?
Tension in the string changes along the vertical circular path. Speed of the ball changes as the sum of kinetic energy and potential energy remains constant during motion. Speed changes, hence, centripetal force changes. So, the correct answer is Earth’s pull on the ball.
Which part of the string will break first when the set up is given a quick jerk?
A quick jerk on the lower string will break that string but a slow pull on the lower string will break the upper string.
Which law of motion describe the motion of the ball before and after the string snapped?
If the string breaks, the ball will move off in a straight line. The straight line motion in the absence of the constraining force is an example of Newton’s first law.
What is the law of inertia in physics?
Newton’s First Law of Motion (Inertia) An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.
What happens to the direction of the iron ball if the string suddenly breaks?
If the string breaks, the ball flies off in a straight- line path in the direction it was traveling at the instant the string broke. If the string is no longer applying a force to the ball, Newton’s First Law tells us that the ball will continue to move in a straight line.
Has dark matter been proven?
Scientists have not yet observed dark matter directly. It doesn’t interact with baryonic matter and it’s completely invisible to light and other forms of electromagnetic radiation, making dark matter impossible to detect with current instruments.
Are there dimensions we Cannot see?
The things in our daily life have height, width and length. But for someone who’s only known life in two dimensions, 3-D would be impossible to comprehend. And that, according to many researchers, is the reason we can’t see the fourth dimension, or any other dimension beyond that.
How likely is string theory correct?
Polchinski explained a computation that shows that string theory is 98.5% likely to be correct, going on to claim that the probability is actually higher: “something over 3 sigma” (i.e. over 99.7%).
What is the formula of tension in the string?
Solution: We know that the force of tension is calculated using the formula T = mg + ma.
How much force can a string hold?
A string can bear a maximum tension of 100 Newton without breaking. A body of mass 1 kg is attached to one end of 1 m length of thin string and it is revolved in a horizontal plane.
How do you find the tension force on a string?
- Tension formula is articulated as. T=mg+ma.
- Tension Formula is made use of to find the tension force acting on any object. It is useful for problems.
- Tension Solved Examples.
- Problem 1: A 8 Kg mass is dangling at the end of a string.
- Answer:
Does length of rope affect tension?
The lengths of the strings do not affect the tension.
Does tension change with acceleration?
In a typical case of two objects, one pulling another with a rigid link in-between, the higher acceleration of the first results in a higher tension in a link.
Is tension in a rope always the same?
If there is a knot in the rope but the rope is straight and has a negligible mass, the tension will still be constant throughout. If the rope is kinked at some point, though,and head off in different directions from the kink, then the tension may change so that the kink point is held in equilibrium.
Can tension ever zero?
It is never zero . It can be just greater than zero . Because if it would become zero then path will no be actually circular . In what position is tension in a string maximum?
Is centripetal force equal to tension?
Top: the centripetal force on the object equals the tension of the string plus the weight of the ball, both acting toward the center of the vertical circle.
How do you find tension in a string in circular motion?
- Formula for tension = centrifugal force = mv2/r.
- So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)
- The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)