What is a projectile Class 11 answer?

A particle moves along a curved path under constant acceleration when thrown obliquely near the Earth’s surface. This curved path is always directed towards the centre of the Earth. The path of such a particle is called the projectile’s trajectory, and the motion is called projectile motion.

How do you solve projectiles launched at an angle?

How do you answer a projectile motion question?

What is the formula for launch angle?

So our equation for the launch angle of the projectile is 𝜃 equals the inverse sin of the square root of two 𝑔ℎ divided by 𝑉.

Why is 45 degrees the best launch angle?

As ball speed increases, so does the drag force and the lower is the required launch angle. A launch at 45 degrees would allow the ball to remain in the air for a longer time, but it would then be launched at a lower horizontal speed at the start and it would slow down more because of the longer flight time.

Is 45 degrees always the best angle of trajectory?

The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.

What are the 3 types of projectile motion?

  • Oblique projectile motion.
  • Horizontal projectile motion.
  • Projectile motion on an inclined plane.

What is the formula of range in projectile?

Maximum Range of Projectile Now that the range of projectile is given by R = u 2 sin ⁡ 2 θ g , when would be maximum for a given initial velocity .

What is the formula of projectile motion?

The equation for the distance traveled by a projectile being affected by gravity is sin(2θ)v2/g, where θ is the angle, v is the initial velocity and g is acceleration due to gravity.

At what angle of projectile θ is the horizontal range minimum?

The horizontal range will be minimum if the angle of projection is 90°.

What is projectile motion in short answer?

Projectile motion is the motion of an object projected vertically upward into the air and moving under the influence of gravity. Projectile motion is the motion of an object projected horizontally into the air and moving independently of gravity.

How do you calculate launch velocity?

The launch speed is just the distance divided by the time.

How do you find the maximum height of a projectile angle?

  1. if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest.
  2. if α = 45°, then the equation may be written as:
  3. if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that’s the case of horizontal projectile motion.

How does the launch angle affect the distance traveled or range of a projectile?

The highest point in the trajectory occurs at the midpoint of the path. This highest point increases as the angle increases. At a 75° launch angle, the maximum height is approximately 76 meters. However, a further increase in launch angle beyond this 75° angle will increase the peak height even more.

What’s the best launch angle?

A typical attack angle of the barrel on a flyball is +20 to +35. We try to have an attack angle of about 10 degrees. Most professional hitters have a consistent attack angle between +8 to +12 degrees. Most amateur hitters struggle to get through the ball and have a negative attack angle.

How does launch angle affect horizontal distance?

Launch angles closer to 45 ° 45\degree 45° give longer maximum horizontal distance (range) if initial speed is the same (see figure 5 above). These launches have a better balance of the initial velocity components that optimize the horizontal velocity and time in air (see figure 4).

What is the optimum angle to launch a projectile?

For ideal projectile motion, which starts and ends at the same height, maximum range is achieved when the firing angle is 45°. If air resistance is taken into account, the optimal angle is somewhat less than 45° and this is often considered obvious.

At what angle range of projectile is maximum?

The range of a projectile for a given initial velocity is maximum when the angle of projection is 45∘.

What angle can a projectile achieved the shortest distance?

The projectile launched at 30-degrees has the smallest vy, and as such the shortest hang time. The range of a projectile is determined by two parameters – the initial value of the horizontal velocity component and the hang time of the projectile.

What is the best angle to throw a ball at for maximum range?

If there were no air resistance, you would get the maximum distance by throwing at a 45° angle (Figure 3). But there is air resistance, and the faster the ball is thrown, the more air resistance there is. Also, the longer the ball is in the air, the more time there is for air resistance to slow down the ball.

What is projectile example?

you throw the ball straight upward, or you kick a ball and give it a speed at an angle to the horizontal or you just drop things and make them free fall; all these are examples of projectile motion. In projectile motion, gravity is the only force acting on the object.

What is a Type 2 projectile?

A “Type 2” Projectile Motion problem is one where a projectile is launched with a 2D initial velocity vector, and it returns back to the same height when it lands.

What is an example of an object in projectile motion?

Tossing an object into the bin, water flowing from a tap, jumping from a bus, etc are all common examples of projectile motion which we encounter every day. Yes, well-known examples of projectile motion like bullets, slingshots, baseball, rockets are not very common in our daily lives.

What is the formula of velocity in projectile?

Velocity of projectile at any instant can be written, in the vector form, as v → ( t ) = v x i ^ + v y j ^ , where is the component of velocity vector v → ( t ) at time and is its component at that time. So let’s see, what will this expression be, in terms of initial speed and projection angle .

What is maximum height of a projectile?

Thus, the maximum height of the projectile formula is, H = u 2 sin 2 θ 2 g .

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